13.1.2 Rotation of mirror

Let f be angle of incidence in first position of mirror M1 M2. Further, let mirror is rotated through angle q, then normal will also rotate by same angle is same sense.

d1 = Deviation in first position of mirror

= p – 2f

d2 = Deviation in second position of mirror

= p – 2 (q + f)

\ d1 – d2 = p – 2f – {p – 2(q + f)} = 2q

Thus, the angle turned by the reflected ray is twice the angle turned by the mirror.

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