# Physics Assignment Help With Work

## Work Assignment Help

The work*W*done by a constant force

*F*when its

*point of application*undergoes a displacement

*s*is defined to be

*W*=*F s*cos**q**

where

**q**is the angle between and as indicated in figure. Only the component of along

*s*, that is,

*F cos*q, contributes to the work done. Strictly speaking, the work is done by the

*source*or

*agent*that applies the force. Work is a

*scalar*quantity and its

*SI*unit is the

*joule (J)*.

*Work*is also defined as the

*dot product of force and its displacement*as given by equation

*W*=

In terms of rectangular components, the two vectors are =

*Fx*+

*Fy*+

*Fz*and

= D

*x*+ D

*y*+ D

*z*;

hence, the definition of work may be written as

*W*=

*Fx*D

*x*+

*Fy*D

*y*+

*Fz*D

*z*

The work done by a given force on a body depends only on the

*force*, the

*displacement*, and the

*angle*between them. It does not depend on the velocity or the acceleration of the body, or on the presence of other forces.

Since the work is a scalar, its value also does not depend on the orientation of the coordinate axes. Since the magnitude of a displacement in a given time interval depends on the velocity of the

*frame of reference*used to measure the displacement,

*the calculated work also depends on the reference frame*.

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