Chemistry Assignment Help with Degree of Dissociation

5.8 Degree of Dissociation

Degree of dissociation is the fraction of a mole of the reactant that underwent dissociation. It is represented by ‘a’.

molar concentration 

5.9 Relation between Vapour Density and Degree of Dissociation

Chemistry Assignment Help Order Now The relation between vapour density and the degree of dissociation can be established only for a gaseous equilibrium who’s KP exists. For example,

law of mass action2

Total concentration at equilibrium = c – ca + nca = c [1 – a + na] = c [1 + a (n – 1)]

Assuming that all the gaseous components at equilibrium behave ideally, we can apply ideal gas equation.

PV = nR = reversible reactions

equilibrium constant

\ V.D = gas equation                                  …(i)     [since molar mass = 2 ´ V.D]

As pressure of the system is given by, equilibrium, so putting the value of P in equation (i) gives

V.D = chemistry help

where r is the density of the gas or gaseous mixture expressed in g/litre.

If the equilibrium reaction is established in a closed vessel, then vapor density will be inversely proportional to the number of moles of the gaseous species as the density of the gaseous mixture (r) is a constant.

\chemistry assignment

Let the initial vapour density and vapour density at equilibrium be ‘D’ and ‘d’ respectively, then for the given equilibrium

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or chemistry equations

or equilibrium reactions

\ pressure-equilibrium2

where ‘n’ represents the number of moles of gaseous product given by 1 mole of the gaseous reactant.

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