Electromagnetic & Electromechanical Energy Conversion [ELEN2001] SEMESTER 2 Curtin University School of Elec Eng, Comp and Math Sci (EECMS)
In all calculations the minimum amount of work (presentation) for each stage of the solution is:
(v) answer.
Only S.I. units are to be used for answers, eg. Newton-metres (Nm) for torque.
Assignment Office (204-Level 2 foyer).
Assignment must be submitted in a plastic sleeve, with a copy of the Assignment question sheets as obtained from blackboard and the university assignment attachment sheet.
Assignment may be hand written but must be using the requested formats.
NOTE: It is recognised that everyone has a different style and layout when completing homework questions and therefore COPYING and PLAGURISM will attract a marks penalty.
An example of the use of diagrams and solution layout for your assignment is shown below.
Note: Most problems can be solved by more than one way, any valid method is acceptable. It is unlikely that all students would use the same method or formatting. Identical method and formatting will be investigated as not being an individuals own work.
EXAMPLE
A 10 kW, 125 V, 4 pole, compound generator has rotational losses of P_{W} = 580 W. The shunt field resistance R_{f} = 62.5 Ω, the lap connected armature resistance
R_{a} = 0.12 Ω, and the series field resistance R_{s} = 0.022 Ω.
Calculate the full load efficiency if the generator is connected long shunt.
Solution.
(i) Circuit
Total armature current:
(ii) Equation (iv) Substitute (v) Answer.
QUESTION 1. [25 Marks]
In the magnetic circuit shown in Figure 1, a 400 turn coil on the left leg of the core is required to produce a flux of 1.4 mWb in the right leg. The thickness of the magnetic circuit is 0.04 m and is uniform throughout the core. The magnetic circuit is constructed with laminated silicon steel the characteristics of which are given below
A 40 kVA step up single phase transformer has the following name plate ratings:
Power |
40 kVA |
Frequency |
50 Hz |
Phases |
1 |
Primary voltage |
415 V |
Secondary voltage |
1100 V |
Insulation |
Class H |
The results from an open circuit and short circuit tests are as follows:
Open circuit test
(Performed on secondary with primary open circuited)
V_{OC }= 1100 V
I_{OC} = 1.82 A
P_{OC} = 320 W
Short circuit test
(performed on primary with secondary short circuited)
V_{SC} = 19.5 V
I_{SC} = 96.4 A
P_{SC} = 800 W
From these test results determine:
(This problem illustrates the principles of dynamometer-type ac ammeter.) Two coils, one mounted on a stator and the other on a rotor, have self- and mutual inductances of
L_{11} = 3.5mH L_{22} = 1.8mH L_{12} = 2.1 cos θ mH
where θ is the angle between the axes of the coils. The coils are connected in series and carry a current
i = √2 I sin ωt
A three phase induction motor with "Design B" characteristics has the motor name plate details are as follows:
Power |
7.5 kW |
Voltage |
415 V |
Poles |
4 |
Current |
14.4 A |
Speed |
1425 rpm |
Connection |
Delta |
Frequency |
50 Hz |
NEMA Design |
B |
The rotational losses (Friction and Windage losses) at full load are P_{f/w} = 0.315 kW.
R_{1} = 1.745 Ω |
X_{1} = j7.90 Ω |
R_{2}‘ = 2.37 Ω |
X_{2}‘ = j11.85 Ω |
R_{C} = 1670 Ω |
X_{M} = j245 Ω |
For the above motor:
Using the above complete equivalent circuit and assuming rated voltage operation, determine:
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