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Asked By :  Jonnathan
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Two sport teams are tied each having won five games and lost th

Two sport teams are tied, each having won five games and lost three. If one of the teams wins the next two games and the other loses the next two games, by how much will the teams' winning percentages differ?




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To find the difference in winning percentages between the two sport teams after the next two games, we need to calculate the winning percentages for both teams before and after the two games.

  1. Calculate the current winning percentage: Each team has won 5 games and lost 3 games. Thus, they each have played 8 games.

    Winning percentage PP is given by:

    P=Number of WinsTotal Number of Games×100P = \frac{\text{Number of Wins}}{\text{Total Number of Games}} \times 100

    For both teams currently:

    P=58×100=62.5%P = \frac{5}{8} \times 100 = 62.5\%
  2. Determine the number of wins and losses after the next two games:

    • Team A wins the next two games, so their new record will be 7 wins and 3 losses.
    • Team B loses the next two games, so their new record will be 5 wins and 5 losses.
  3. Calculate the new winning percentages:

    • For Team A:

      PA=77+3×100=710×100=70%P_A = \frac{7}{7+3} \times 100 = \frac{7}{10} \times 100 = 70\%
    • For Team B:

      PB=55+5×100=510×100=50%P_B = \frac{5}{5+5} \times 100 = \frac{5}{10} \times 100 = 50\%
  4. Compute the difference in winning percentages:

    Difference=PAPB=70%50%=20%\text{Difference} = P_A - P_B = 70\% - 50\% = 20\%

The teams' winning percentages will differ by 20 percentage points after the next two games.


Answered By

Timothy Smith

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