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Asked By :  Sukhdev
Answers1

To get to his office from home greg walks 5 blocks north and

To get to his office from home, Greg walks 5 blocks north and then 2 blocks east. After work he meets some friends at a cafe; to get there he walks 3 blocks south and 5 blocks west. All blocks are 660 feet long.

What is the straight-line distance from the cafe to his home?




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0

Greg’s net displacement from home to the café (or café to home) is 3 blocks west and 2 blocks north. The straight‐line distance DD is therefore

D=(3blocks)2+(2blocks)2×660 ft=9+4×660 ft=13×660 ft2380.6 ft.D = \sqrt{(3\,\text{blocks})^2 + (2\,\text{blocks})^2}\times 660\ \text{ft} = \sqrt{9 + 4}\times 660\ \text{ft} = \sqrt{13}\times 660\ \text{ft} \approx 2380.6\ \text{ft}.

So the café is about 2 380.6 feet from Greg’s home in a straight line.



Answered By

Sukhdev

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