Questions

To determine the force experienced by the wire due to the Earth's magnetic field, we can use the formula for the magnetic force on a current-carrying wire:

where:

• $F$ is the force on the wire,
• $I$ is the current flowing through the wire ($0.70 \, \text{A}$ in this case),
• $L$ is the length of the wire ($1.00 \, \text{m}$),
• $B$ is the magnetic field strength ($0.65 \, \mu\text{T} = 0.65 \times 10^{-6} \, \text{T}$),
• $\theta$ is the angle between the direction of the current and the magnetic field.

In this scenario, the current is directed [right] and the magnetic field is [down]. Since the current direction and magnetic field are perpendicular to each other, $\theta = 90^\circ$ and $\sin(90^\circ) = 1$.

Plugging the values into the formula, we get:

The direction of the force can be determined using the right-hand rule: point your thumb in the direction of the current ([right]), and your fingers in the direction of the magnetic field ([down]). Your palm will face the direction of the force experienced by the wire, which will be out of the page or [toward you].

Thus, the force experienced by the wire is $4.55 \times 10^{-7} \, \text{N}$ [toward you].