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Asked By :  Bradley
Answers1

Fie x1x1 i x2x2 soluiile ecuaiei x7x13x3xx0beginvmatrix

Fie x1x_1 și x2x_2 soluțiile ecuației

x+7x13x3xx=0.\begin{vmatrix} \frac{x+7}{x-1} & \frac{3}{x} \\ \frac{3}{x} & x \end{vmatrix} = 0.

Calculați x12+x22x_1^2 + x_2^2. (9 pct.)**
a) 7
b) 8
c) 12
d) 9
e) 10
f) 11




Answers :

0

Determinantul dat conduce la o ecuație de gradul 2. Folosind suma și produsul rădăcinilor,


x12+x22=(x1+x2)22x1x2x_1^2 + x_2^2 = (x_1 + x_2)^2 - 2x_1x_2. Rezolvând, obținem x12+x22=12x_1^2 + x_2^2 = 12.


Răspuns corect: c) 12



Answered By

Andrea

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