Questions

Let's address each question one by one:

Part (d)

Monomer: Ethyne (Acetylene), represented as $H-C \equiv C-H$.

Task: Draw the polymer created when 3 ethyne monomers are linked together.

Ethyne can undergo polymerization typically through a reaction known as "chain-growth polymerization" where triple bonds convert to single bonds to form a long chain.

Polymer from 3 Ethyne Monomers: $H-(C\equivC)-(C\equivC)-(C\equivC)-H$

However, when these monomers link, they form a linear chain:

$-[H-C\equivC-C\equivC-C\equivC-H]-$

The reaction type is Polymerization.

Part (e)

Reactants:

1. Propanol $(\text{CH}_3-\text{CH}(\text{OH})-\text{CH}_3)$
2. Cyclopentanol $(\text{cyclopentane with an -OH group)})$

The given reaction type symbol (a delta above the arrow) typically indicates heating, suggesting a reaction such as dehydration.

Reactants and Products:

• Alcohols (Propanol and Cyclopentanol) can undergo a dehydration reaction upon heating in presence of a strong acid.
• Dehydration of alcohols leads to the formation of alkenes and water.

When these two alcohols undergo dehydration, they form the respective alkenes, typically:

1. Propene
2. Cyclopentene

Reaction Products: $CH_3-CH=CH_2$ (Propene) $\text{and}$ the alkene form of cyclopentanol:

The reaction type here is Dehydration Reaction.

Summary:

• Part (d) Reaction Type: Polymerization
• Part (e) Reaction Type: Dehydration Reaction

Products:

1. For propanol: $CH_3-CH=CH_2$ (Propene)
2. For cyclopentanol: Cyclopentene

         H    H

        |      |
H-C=C - C=C-C

would this be correct?