Using euler methods

1. Using Euler Method

s= 0.08*v^1.3 - 3

dt = 0.5 sec % taking one step

n = 2

s1 = s1 + f*dt = 0 + dt*(s1+3)/0.08) ^1/1.3

s2 = 8.12 + 1*((8.12-3)/0.08)^1/1.3 = 30.37

tn =1 % max time

h = (tn - t0)/n = 1

s1 = s0+0.5*k1*h = 0 +0.5*8.12*1 = 4.06

f2= (s1+3)/0.08) ^1/1.3 =(8.12+3)/0.08) ^1/1.3 = 31.58

s3 = s0+0.5*k3*h = 0 +0.5*66.9*1 = 33.45

f4= (s3+3)/0.08) ^1/1.3 =(33.45+3)/0.08) ^1/1.3 = 110.9

3. Using Matlab