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the variable defined and initialized with the valu

The variable defined and initialized with the value the beginning

Variable shadowing Assignment Answers

Question:

int z = 10;

cout << "something else";

}

Variable shadowing Answer and Explanation

1. The outer `z` is initialized to `10`.

2. The first `for` loop declares a new `int z`, which is scoped only within the loop. This local `z` starts at `0` and increments up to `3` (less than `4`). Inside this loop, `"something"` is printed four times.

something

something

10

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