The single-pass conversion and reactor balances
Solution
Basis: 100 mol Combined Feed to the Reactor
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n4 mol CO2 /mol
x4 mol CO2 /mol
3x4 mol H2 /mol
(1-4x4) mol I/mol
Take a moment to examine the chart labeling. In particular, notice that we have built in the facts that CO2 and H2 are always present in a 1:3 ratio and that the compositions of the gaseous effluent from the condenser, the purge stream, and the recycle stream are all identical. The more of this sort of information you can incorporate in the chart labeling, the easier the subsequent calculations become. Let us outline the solution, referring to the flowchart.
60% Single-Pass Conversion
| n 1 | = |
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24 5. ) | = | .9 80 | mol | CO | 2 | output | = | ||||||||||||
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| = | 29 4. | mol | H | 2 | ||||||||||||||||||
| = | 14 | 7. | mol | CO | 2 | |||||||||||||||||
| n 2 | ⇓ |
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on | CH | 3 | OH | , | H | 2 | O | : | |||||||||||
| = | 14 7. | mol | CH | 3 |
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| n 3 | = | 14 | 7. | mol | H | 2 | ||||||||||||||||
CO2 Balance About Condenser
| n 1 | = | n 4 |
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I Balance About Mixing Point
no = 65.4 mol fresh feed
n6 = 34.6 mol recycleMole balance About Purge Takeoff
| n 4 | = | n 5 | + |
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| [ ( 1000 | mol | / | h | ) | / | n 2 | mol ] | n | 2 | = 14 7.
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6 .8 03 | h | − |
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