The rankine cycle more realistic model for steam power plants

Rankine Cycle Efficiency Homework Answers Needed

Your Question:

Part (a)

Minimum heat rejection from the condenser:

Hence, the minimum heat rejection from the condenser is:

Qout = h4 - h1

Thermal efficiency of the cycle:

η = (Win - Wout) / Qin

Assuming isentropic processes for the pump and turbine:

Win = h2 - h1

Win = 722.62 - 697.14 = 25.48 kJ/kg

Wout = 3354.1 - 977.5 = 2376.6 kJ/kg

Part (b)

Sketch of the Rankine cycle on a T-S diagram:

Part (c)

Comparison of the thermal efficiency of the Rankine cycle with the equivalent Carnot cycle thermal efficiency:

• Tlow = temperature of the low-temperature reservoir

• Thigh = temperature of the high-temperature reservoir