The perimeter oftriangle xyz express terms the cosine rule
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Thursday 4 May 2006 (morning)
1 hour 30 minutes
2206-7304 7 pages
– 2 – M06/5/MATME/SP2/ENG/TZ2/XX
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5 and g x ( ) = x | ||||||||||||||||||||||||||||||||||||||||||
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−1 | ( ) | = | x | + | 2 | , find ( | g | −1 o | f | )( ) | . | [2 marks] | ||||||||||||||||||||||||||||
(c) | f | −1 | o | g | )( ) | = | x | + | 3 | , solve ( | f | −1 | o | g | )( ) | = | ( | g | −1 | o | f | )( ) | [2 marks] | |||||||||||||||||||
3 | ||||||||||||||||||||||||||||||||||||||||||
= | g x ( ) , |
x | ≠ 2. | |||||||||||||||||||||||||||||||||||||||
(d) | (i) |
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x | ≤ | 7 | and − ≤ | y | ≤ | 8 |
(f) | (i) | 5∫ | h x ( )dx | [5 marks] | |||||
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(ii) | 5∫ | h x ( )dx |
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2206-7304 | Turn over |
(ii) this maximum value of y. [4 marks]
The triangle XYZ has XZ = 6, YZ = ,x XY = z as shown below. The perimeter of
(c) | 2 | = 9 | x | 2 | sin | 2 | Z |
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= −16 2 | + | 160 | x | − | 256 | [4 marks] | ||||||||||
(e) | (i) | [3 marks] | ||||||||||||||||
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In the group of fourteen-year-old students, 60 % are girls and 40 % are boys. The probability that a girl is taller than 170 cm was found in part (a).
The probability that a boy is taller than 170 cm is 0.202 .
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2206-7304
– 7 – M06/5/MATME/SP2/ENG/TZ2/XX
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