Code Tracing and Corrections Homework Answers Needed
Your Question:
What is the trace of this code after running it?
Step By Step Answers with Explanation
String str = "HELLO-WORLD!!";
String[] a = {"3", "4", "35", "0", "27", "0", "0", "90", "40", "55", "68"};
int x = Integer.parseInt(a[i + 1]);
int y = Integer.parseInt(b[i]);
int x = Integer.parseInt(b[1 - 2]);
int y = Integer.parseInt(a[i]);
} catch (ArrayIndexOutOfBoundsException e) {
System.out.println("Array Out of Bounds");
}
}
1. `String str = "HELLO-WORLD!!";`: This line initializes a string variable `str` with the value "HELLO-WORLD!!".
2. `String[] a = {...};` and `String[] b = {...};`: These lines create two arrays `a` and `b` with some string values.
- `int x = Integer.parseInt(a[i + 1]);`: This line tries to parse `a[i + 1]` as an integer.
- `int y = Integer.parseInt(b[i]);`: This line tries to parse `b[i]` as an integer.
- `int x = Integer.parseInt(b[1 - 2]);`: This line tries to parse `b[-1]`, which will result in an exception.
- `int y = Integer.parseInt(a[i]);`: This line tries to parse `a[i]` as an integer.
- `StringIndexOutOfBoundsException`: This block catches string index out-of-bounds exceptions and prints "String Out of Bounds" if one occurs.
- `NumberFormatException`: This block catches number format exceptions and prints "Can't convert." if one occurs.
4. Parsing `a[1]` as an integer (`x = 4`) and `b[0]` as an integer (`y = 12`) are successful.
5. `System.out.println(x / y);` prints `0` because `4 / 12 = 0`.
- `i = 1`: The code encounters an arithmetic exception when trying to divide by zero (`4 / 0`).
- `i = 2`: The code successfully calculates `35 / 0` and prints `Infinity` (since dividing by zero in Java results in positive or negative infinity).
- `i = 7`: The code encounters an array index out-of-bounds exception when trying to access `b[1 - 2]` (`b[-1]` is out of bounds).
- `i = 8`: The code successfully calculates `90 / 40` and prints `2`.