Receivers would waiting infinitely till the senders send new packet
Data Communications
Exam 1
Answer:
Receivers and senders should know ip in advance to start the communication. In another word both shall know address of each other before they can send actual message.
Answer:
Number of packet for size m= 1 Mega / m
TD = 50x 1 Mega / 1000 + 1000 = 50,000 + 1000 = 51,000
For m = 10,000
File server
Print server
Video streaming (for example, Netflix)
Answer:
| Application | Average bandwidth | Peak bandwidth | Latency | Jitter | Loss tolerance |
|---|---|---|---|---|---|
| File Server | Medium | High | Low | Low | Low |
| Print Server | Low | Low | Low | Low | Low |
| Digital Library | Low | High | High | High | Low |
| Routine monitoring of remote weather instruments | Medium | Low | High | High | Low |
| Voice | Medium | Medium | Low | Low | Low |
| Video monitoring of a waiting room | Medium | High | High | High | High |
| Video streaming | High | High | High | High | High |
Manchester
NRZI (starts low)
Assume the following Ethernet network segment:
The cable connecting device C to Network device B1 is most likely to be _______ Fast Ethernet ___________.
Assume that you are designing a network for an office located on one floor of the C-shaped office building below.
We can’t use one single switch to cover 300 meters. As communication would be poor. Mostly packet will be lost.
Is it possible to network this entire floor two Fast Ethernet (100 Mbps) switches? (No other interconnection hardware can be used.) Why or why not?
Answer: Step1: Packet travel into Switch
Step 2: Switch added the frame into receiving bit stream
Step 7: if MAC address found, it forwards to corresponding IP host(148.100.13.9)
Describe the path an IP packet will take traveling the host 148.100.12.2 to 148.100.20.30. (Don’t worry about message processing on the hosts; just talk about the hosts, network, and/or routers that will handle the packet.)
Step 4: Router search the given network from routing table
Step 5: No network (148.100.20.0) in routing table
Answer: Let us discuss the given Ethernet segment by considering it as comprising two divisions – Left and Right networks. As for as the left network (ring topology) is concerned, we could assure maximum reliability but it has more redundancy. This Ethernet segment in this network requires more cost and involves more complexity. One of the drawbacks of this Ethernet segment is that there would be broadcast collision. On the other hand, there is no reliability in the right Ethernet segment division
Compare and contrast Ethernet hubs, Ethernet switches, and routers by filling in the table below:
