Solved step by step with explanation - Metal Properties and Calculations

Question

Solved step by step with explanation - Metal Properties and Calculations

a) Flow Stress at True Strain = 1.0:

1. Given data: Strain-hardening exponent (n) = 0.20, Strength coefficient (K) = 400 MPa, True strain (ε) = 1.0.

1. Given data: Strain-hardening exponent (n) = 0.20, Strength coefficient (K) = 400 MPa, Flow stress (σ) = 400 MPa.

2. Rearrange the flow stress equation to solve for true strain: ε = (σ / K)^(1/n), where ε is the true strain.

1. Tensile strength is the maximum engineering stress reached during the tensile test. It is located at the end of the stress-strain curve.

2. Tensile strength (σ_ts) can be determined using the flow stress equation: σ_ts = K ε^n, where ε is the true strain at failure.

To summarize, for Problem 3.5, the flow stress at a true strain of 1.0 is 400 MPa, and the true strain at a flow stress of 400 MPa is 1.0. For Problem 3.6, the tensile strength for the metal with the given parameters is 350 MPa. This calculation assumes that the material is elongated to twice its original length at failure.