Your Question:

If the wire in a solenoid coil has 10 turns and 5 amperes of current flow through it, what is the magnetic field strength of the coil?

Step By Step Answers with Explanation

A solenoid is a long, thin coil of wire with a uniform number of turns per unit length. When a current flows through the coil, it creates a magnetic field inside the solenoid. The magnetic field strength is proportional to the number of turns per unit length and the current flowing through the coil.

To calculate the magnetic field strength inside a solenoid, we can use the following equation:

* B is the magnetic field strength in Tesla (T)

* μ₀ is the permeability of free space, which is equal to 4π × 10⁻⁷ T⋅m/A

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B = μ₀ * n * I / 2

B = (4π × 10⁻⁷ T⋅m/A) * (10 turns/m) * (5 A) / 2

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To explain this further, imagine a solenoid as a long tube with many small magnets wrapped around it. The North poles of all the magnets are facing in the same direction, and the South poles are facing in the opposite direction. When a current flows through the solenoid, the magnetic fields of all the magnets add together, creating a uniform magnetic field inside the solenoid.

The stronger the current and the more turns of wire, the stronger the magnetic field. This is why solenoids are used to create strong magnetic fields, such as in MRI machines and loudspeakers.