logical inconsistencies Assignment Answers

Question:

logical inconsistencies Answer and Explanation

    int x = 7;

    int y = 10;

    result += (y + 1) * 11 && (z++ >= 6 || x++);

    printf("result: %d\n", result);

}

Now let's analyze the code step by step:

- `result = 0`

2. First expression:

- `110 | 0` results in `110` (bitwise OR).

- `110 && x++` results in `1` (since `110` is non-zero, `x++` is evaluated).

- `y++` evaluates to 11 and increments `y` to 12.

- `11 * 5` results in `55`.

result += (y + 1) * 11 && (z++ >= 6 || x++);

- `y + 1` results in `13`.

- `0 || x++` results in `1` (since `x++` is evaluated).

- `x++` increments `x` to 10.

- `y: 12`

- `z: 6`

2. Second line of output:

- `x: 10`

4. Fourth line of output:

- `z: 6`