End tree getsum printtreepostorder are almost done

If you are willing to play along with this definition, it has a nice property: we can represent any expression (without parentheses) as a sum of products. This property is the basis of our parsing algorithm.

getSum tries to build a tree with a product on the left and a sum on the right. But if it doesn’t find a +, it just builds a product.

def getNumber(tokenList):
if getToken(tokenList, ’(’):

x = getSum(tokenList)
getToken(tokenList, ’)’) return x
else:
x = tokenList[0]

The parser handled the parentheses correctly; the addition happens before the multiplication.

In the final version of the program, it would be a good idea to give getNumber a name more descriptive of its new role.

x = getSum(tokenList)

if not getToken(tokenList, ’)’):

The raise statement creates an exception; in this case we create a new kind of exception, called a BadExpressionError. If the function that called getNumber, or one of the other functions in the traceback, handles the exception, then the program can continue. Otherwise, Python will print an error message and quit.

As an exercise, find other places in these functions where errors can occur and add appropriate raise statements. Test your code with improperly formed expressions.