Determine the reactions both the wheels and both the wheels

Solved Step by Step With Explanation- Cart Forces and Acceleration

Questions

Solved Step by Step With Explanation- Solved Step by Step With Explanation- Cart Forces and Acceleration

Answer

1. Reaction at Wheels A: Let's consider the forces acting on the cart in the vertical direction. At Wheel A, we have the following forces:

• The weight of the cart (mg) acting downward, where g is the acceleration due to gravity (approximately 9.81 m/s²).

R_A = 60 kg * 9.81 m/s² = 588.6 N

2. Reaction at Wheels B: At Wheel B, the forces are the same as at A because the cart is uniform and balanced.

F_friction = μ * R

Where μ is the coefficient of friction and R is the normal reaction force.

F_net = 300 N - 176.58 N

= 123.42 N

≈ 2.06 m/s²

So, the acceleration of the cart is approximately 2.06 m/s².