Cylinder orientation the cylinder vertical and fully submerged
MODULE I:
1. Differentiate Atmospheric Pressure, Gauge Pressure, and Absolute Pressure.
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Pabsolute=Pgauge+Patmospheric
Key Differences:
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2. Define Fluids, Capillarity, and Surface Tension.
Fluids:
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| o | Compressibility: Gases are highly compressible, whereas liquids are | |
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Capillarity (Capillary Action):
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| o | Adhesion: Attraction between fluid molecules and the surface of the | |
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| o | Molecules at the surface experience a net inward force because they | |
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U-tube Manometer:
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Key Differences:
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| o | U-tube Manometer: Measures the pressure difference between two | |
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| o | U-tube Manometer: Indicates the pressure difference based on the | |
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4. Explain Total Pressure and Centre of Pressure.
Total Pressure:
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| Ptotal=Pstatic+1 2ρv | |||
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Centre of Pressure:
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hc p=I Gˉ
A⋅y
I G: Second moment of area about the horizontal axis through the centroid
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1. Positive Metacentric Height (GM > 0):
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o Condition: The metacenter (M) is below the center of gravity (G).
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Factors Affecting Stability:
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Applications:
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| o | Instantaneous: Represents the flow direction at a specific moment. | |
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| o | Change with Time in Unsteady Flow: In unsteady flow, streaklines | |
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| o | Variable in Unsteady Flow: In unsteady flow, pathlines can diverge | |
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through a fixed |
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Coincides with | |
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| Unsteady Flow | independently | ||
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Understanding these concepts is crucial for analyzing and visualizing different
aspects of fluid flow, especially in complex and unsteady flow conditions.
Assumptions and Given Data:
1. Conical Vessel Dimensions:
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o The pressure at outlet A is atmospheric pressure.
| | o | The manometer shows a reading of 20 cm, which likely represents a |
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Solution Approach:
1. Determine the Hydrostatic Pressure Due to Water:o Hydrostatic Pressure (P):
2. Relate Hydrostatic Pressure to Manometer Reading:
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| Δ h= | 29,430Pa |
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| 13,600 kg/m | 3×9.81m/s | ||||
Total Manometer Reading=20cm+22cm=42cm
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The vertical reaction at point B.
Assumptions:
1. Hydrostatic Conditions: The water is at rest, and pressure varies with depth.
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Step 1: Calculate the Hydrostatic Pressure Acting on the Cylinder
ρ = Density of water
g = Acceleration due to gravity
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Where:
Therefore:
o y1=3 m−1.5 m=1.5m (Top of the cylinder)
| F1000 kg/m | 3×9.81m/s | 2×4m × | (4.5 2−1.5 2) | |
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| H= | 2 | |||
| FH=1000×9.81×4× | (20.25−2.25) | |||
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| FH=1000×9.81×4×18 2 | ||||
FH=353,160N=353.16kN
Interpretation:
Step 2: Determine the Horizontal Reaction at Point A (RA)
Horizontal Reaction (RA) must balance the hydrostatic force.
The vertical reaction must balance the weight of the cylinder.
RB=W =196.2kN



