Consider the internal resistance the voltmeter and the ammeter

Solved Step by Step With Explanation- Measurement Errors in Series Circuit

Questions

Solved Step by Step With Explanation- Measurement Errors in Series Circuit

Answer

This is the ideal current without any measurement errors.

(When the voltmeter is connected nearer to the lamp than the ammeter):

Now, we use this current to calculate the actual power consumed by the 80Ω lamp:

P_actual = I^2 * R = (1.0003)^2 * 80Ω = 79.92W

= (79.92 - 79.98) / 79.92 * 100

≈ 0.0175%

I = 1.0003A (approximately)

Now, we use this current to calculate the actual power consumed by the 80Ω lamp, which remains the same as in step 2a:

= 79.96W

The error in measurement is calculated as:

b) When the ammeter is connected nearer to the lamp than the voltmeter, the error in measurement of power is approximately 0.05%.