Code output analysis Assignment Answers

Question:

Code output analysis Answer and Explanation

- `10/3` results in `3` (since it's integer division).

- `"2" + 10 + " " + "3" + 2` results in `"2 32"`.

System.out.printf("%d", ((a-30) > b) ? (a+b): (a-b));

- `a = 20`

- Output: `-30`

Code Segment c

Code Segment d

int x = 4;

- `x < 3` is `false` because `4 < 3` is `false`

- `y < 3` is `false` because `5 < 3` is `false`

int p = ++x;

int z = ++p;

- `x + p - z` which is `11 + 12 - 12` is `11`

- Output: `11`

do {

System.out.printf("%d %d\n", a, b);

- When `a = 10`, `b = 10`, prints `10 10`

- When `a = 15`, `b = 10`, prints `15 10`

Code Segment g

for(int i = 1; i < 10; i += 6) {

break;

System.out.printf("%d %d\n", i, j);

- prints `1 1` and `1 11`

- `i = 7`, `j = 1, 6, 11`

1 11

7 1

3

true

1 11

7 1