b. By using the vector method, calculate the magnitude of velocity at point B and its direction at this instance.

c. Determine a suitable length for link AB so that it can rotate CCW with angular velocity of 2.15 rad/s at this instance and calculate the velocity of slider A.

Solved step by step with explanation: Determine a suitable length for link.

3. Link BC: Link BC is connected to Link AB and is inclined at an angle of 28°1 with the horizontal. It can both translate and rotate. However, since the rotational component depends on the translation of Link AB, we can consider the dominant motion as translation. Therefore, the type of rigid-body motion for Link BC is translation.

The positive direction for translation is along the horizontal axis (to the right), and the positive direction for rotation is counterclockwise.

Magnitude of velocity at B = sqrt((V_A)^2 + (R_AB * w_AB)^2)

where R_AB is the distance from point A to point B and w_AB is the angular velocity of Link AB.

Velocity of Slider A = angular velocity of Link AB * L_AB

Assuming that BC = 2.3 m and the angular velocity of Link AB is 3.6 rad/s, we can calculate the values as follows:

To find the suitable length for Link AB (L_AB), we can use the given angular velocity of Link AB and the distance BC.

L_AB = BC / (angular velocity of Link AB)

= 3.6 rad/s * 0.639 m

≈ 2.3064 m/s