Step By Step Answers with Explanation

The diagram shows a beam with a ball on it, supported by two columns at A and B, and subjected to a load of 108 kN at point C. The beam has a Young's modulus of 200 GPa and a moment of inertia of 445.4 (10^6) mm^4.

To solve this problem, we can use the three-moment equation. The three-moment equation is a differential equation that describes the relationship between the bending moments at three consecutive supports of a beam.

• E is the Young's modulus of the beam

• I is the moment of inertia of the beam

M_A + 2 * M_B + M_C = 6 * 200 * 10^9 * 445.4 * 10^-6 * 4540 / 10^2

M_A + 2 * M_B + M_C = 108 * 10^6 Nmm

Substituting the value of M_C from the three-moment equation into the above equations, we get:

R_A + R_B = 108 kN

R_A = 56 kN

R_B = 52 kN