[ahwriter]

Email me your assignments and I will send you back the solutions.
In addition to solving problems I do projects, papers and essays.
I offer assistance in the following areas, undergraduate, graduate and post graduate levels:
Accounting
Accounting concept
Income statement
Balance sheet
Cash-flow statement
Accounts receivable, Note receivable
Inventory
Fixed Assets, Depreciation
Intangible assets
Current liability
Bond
Long-term liability
Common and preferred stock
Treasury stock
Cash and dividends
Financial statement analysis
Cost accounting, Cost analysis
Accounting and management decision
Budgeting
http://www.assignmenthelp.net

[ahwriter]

Yes I meant the detailed Summary shows the Q3 allocation by source wrong, which matches my T3, so my T3 is also wrong. I tracked the problem to Q3 when I can’t match the ROC and eligible dividend numbers on the T3 to slipring iShares’s numbers. I already sent an email to iTrade so hopefully it will get resolved!

[ahwriter]

I got slip rings my T3’s and the Summary of Trust Income from iScotia on Tuesday of this week. Where BMO IL puts all the data on one T3 and breaks it out on the Summary, iScotia provides a T3 for each stock (in my case I’m talking about iShares units) and a separate Summary for each one. No biggee, just interesting the differences and due to BMO IL’s formatting of the iShares names, iScotia’s Summaries are clearer.

[ahwriter]

Hg(OH)2- mercury (II) hydroxide

H2S- Hydrogen sulphide

Ca3N2- Calcium Nitride

[ahwriter]

hi tutor, hmm nicely explain? b/w are you tutor in here cuz I am also trying to become active member and I can answer all question in physical chemistry including mole concept too.

thanks

[ahwriter]

One billion.

[ahwriter]

no sorry that was a mistake….

a + bx + cx2 + dx3 + ex4

a+ x*(b+c*x) + x*x*X*(d+e*x)

a+ x* [(b+c*x) + x*x*(d+e*x)]

so it should be 5…

[ahwriter]

The minimum number of multiplications required to evaluate the expression

a + bx + cx2 + dx3 + ex4 is

1. 4

2. 5

3. 3

4. 7

plz explain…

[ahwriter]

alloc(…) allocates a block of memory for an array of elements of a certain size. By default the block is initialized to 0. The total number of memory allocated will be (number_of_elements * size).

malloc(…) takes in only a single argument which is the memory required in bytes. malloc(…) allocated bytes of memory and not blocks of memory like calloc(…).

[ahwriter]

Why doesn’t the following code give the desired result?

int x = 3000, y = 2000 ;

long int z = x * y ;

[Author]

Posts