a car slows down from a speed of 25.0 m/s to rest 5.00 s. how far did it travel in that time
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a car slows down from a speed of 25.0 m/s to rest 5.00 s. how far did it travel in that time..?
Answer: We know from question that
initial velocity is 25.0 m/s
final velocity is 0 m/s (it is at rest)
By using this formula we can find acceleration:
aav = v/t
a= (25 m/s) / (5 sec)
a= – 5 m/s/s, because it is slowing down
we can use the formula: v2 = u2 + 2as,
(0 m/s)2= (25 m/s)2 + 2(-5 m/s/s) s
0= 625 + (-10) s
-625= (-10) s
s= 62.5 m
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