Forums Science Assignment Help a car slows down from a speed of 25.0 m/s to rest 5.00 s. how far did it travel in that time

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  • #8456
    Anonymous
    Inactive

    a car slows down from a speed of 25.0 m/s to rest 5.00 s. how far did it travel in that time..?

    #15432
    juwanine
    Participant

    answer:- 62.5 m

    #15441
    manjit singh
    Member

    Answer: We know from question that
    initial velocity is 25.0 m/s
    final velocity is 0 m/s (it is at rest)
    By using this formula we can find acceleration:
    aav = v/t
    a= (25 m/s) / (5 sec)
    a= – 5 m/s/s, because it is slowing down
    we can use the formula: v2 = u2 + 2as,
    (0 m/s)2= (25 m/s)2 + 2(-5 m/s/s) s
    0= 625 + (-10) s
    -625= (-10) s
    s= 62.5 m

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