Set of Complex Numbers

We know that the solution of the quadratic equation

ax2 + bx + c = 0, a≠0

are given by quadratic formula

x = -b ± √(b2-4ac)/2a

Now when b2-4ac < 0 the equation cannot be solved in real number system. For this solution, we need the set of complex numbers.

i= √(-1)

The set of complex numbers denoted by ℂ is defined as:

ℂ = {a+bi∶a,b ∈ R,i = √(-1)}

The notation a + bi is called writing complex number in standard form

a is called the real part of complex number z= a + bi (also written as a = Re z) and b is called the imaginary part of complex number z = a+bi (also written as b = Im z ).

Complex Number Examples

Examples of complex numbers can be given as 2+4i or √(-9 )=9i etc.

Two complex numbers z1= a1+b1 i and z2= a2+ b2 i are equal if their real and imaginary parts are equal, which means a1=a2 and b1= b2.

Every real number is a complex number with its imaginary part 0. Thus a = a + 0i

So R ⊂ ℂ

Conjugate of a Complex Number

The complex number z̅= a - bi is called the conjugate of a complex number z = a + bi .

Absolute Value of Complex Numbers

The absolute value of complex number z is defined as |z|= √(a2+b2)

Operations with Complex Numbers

Two complex numbers can be added, subtracted, multiplied and divided resulting in new complex numbers.

If z1= a1 + b1 i and z2 = a2 + b2 i then

Adding Complex Numbers

z1 + z2 = (a1 + a2 ) + (b1 + b2 )i

Subtracting Complex Numbers

z1 - z2 = (a1 - a2 )+(b_1-b_2 )i

Multiplying Complex Numbers

z1 z2 = (a1 a2 - b1 b2 )+(a1 b2 + a2 b1 )i

Dividing Complex Numbers

z1/z2 = a1 + b1 i/a2 + b2 i = (a1 + b1 i)( a2 - b2 i) )/(a2 + b2 i)(a2- b2 i) = (a1 a2+ b1 b2)/(a22 + b22 ) - (a1 b2 + a2 b1)/(a22 + b22 ) i

Then,

1/z= 1/(a+bi)= (a-bi)/((a+bi)(a-bi)) = (a-bi)/(a2+b2 )= a/(a2+b2 ) - b/(a2+b2 ) i

Simplifying Complex Numbers

For simplifying complex numbers we must remember the various powers of imaginary number I, especially while multiplying imaginary numbers:

  • i2 = 1 ,
  • i3 = -i ,
  • i4 = 1 ,
  • i5 = i ,
  • i6 = -1 ,
  • i7 = -i…

Properties of Complex Numbers

  1. complex number math code or the conjugate of the sum of complex numbers is the sum of the conjugates of complex number
  2. 1̅z̅2̅ = z̅1.z̅2 or the conjugate of the product of complex numbers is the product of the conjugates of complex number
  3. z̅. z = |z|2 or the product of the complex number with it’s own conjugate is equal to the square of the absolute value of that complex number
  4. z̅ + z = 2 Re z or the addition of a complex number with its own conjugate is equal to twice the real part of the complex number
  5. z - z̅ =2i Im z or subtracting the conjugate of a complex number from the complex number is equal to two times iota multiplied by the imaginary part of the complex number
  6. Re z ≤ |z| or the real part of the complex number is less than or equal to the absolute value of complex number
  7. z̿ = z or the conjugate of a conjugate of complex number is the complex number itself.
  8. z is real if and only if z̅ = z or if the conjugate of a complex number is equal to the complex number itself then the complex number is a real number, that is it has only a real part and no imaginary part.

Solved Example for Complex Number Properties and Operations with Complex Numbers

Let z1 = 3 - 2i and z2 = -2 + 3i then

Re z1 = 3, Im z1 = -2 and

Re z2 = -2, Im z2 = 3

|z1 | = √(32 + (-2)2 ) = √13

|z2 | = √((-2)2+ 32 )= √13

z1 + z2 = (3-2)+(-2+3)i = 1+i

z1 -z2 = (3 -( -2)) + (-2 -3)i = 5-5i

z1 z2 = (3*(-2)-(-2*3))+(3*3+(-2*-2))i = 13i

z1/z2 = 3-2i/-2+ 3i = 3*(-2) + (-2*3)/4+9 - 3*3 +(-2 * -2))/4+9 i = -12/13 + 13/13 i= -12/13 + i

1/z1 = 1/3-2i = 3/13 + 2/13 i

1/z2 = 1/-2+3i = -2/13 - 3/13 i

1 =3 +2i

2 = -2 -3i

1 + z̅2 = (3 - 2)+(2 - 3)i = 1-i

Hence verified: complex number math code

1 . z̅2 = (3*(-2)-(-2*3)) + (3*-3+(2*-2))i = -13i

1̅z̅2̅ = 1̅3̅i = - 13i

Hence verified: z̅1̅z̅2̅ = z̅1 . z̅2

1.z1 = (3-2i)*(3+2i)=(9+4)+(-2*3+3*2)i=13=(√13)2 = |z1 |2

Hence verified: z̅.z = |z|2

1 + z1 = (3-2i)+(3+2i)= 6 = 2*3 = 2Re z1

Hence verified: z+z̅ = 2 Re z

z1 - z1̅ =(3-2i) - (3+2i) = -4i = 2i(-2) = 2i Im z1

Hence verified: z-z̅ = 2i Im z

Hence verified: Re z ≤ |z|

z̿1 = 3̿-̿2̿i̿ = (3+2i) ̅ = 3-2i = z1

Hence verified: z̿ = z

Applications of Complex Numbers

Complex numbers have vast applications in the field of electrical engineering, study of electrical circuits, trigonometry, calculus, quantum mechanics, and study of waves such as electricity, light, and sound. Or simply in finding square root of negative numbers.

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