The important methods used for the following:
1. Graphical representation/method
A graphical method based on the respective rate laws can also be used.
If the plot of log (ax) versus 't' is a straight line, the reaction follows second order.
If the plot of 1/(ax)^{2} versus 't' is a straight line, the reaction follows third order.
In general, for a reaction of nth order, a graph of 1/(ax)^{n1} versus 't' must be a straight line.
For example of nth order reaction
or
So, from this it is evident that a plot of vs (a – x)^{n} will be straight line passing through the origin and will have its slope equal to k, the rate constant of reaction.
This equation demands that a plot of vs log (a – x)^{n} will be straight line of the slope equal to n, order of reaction and intercept equal to log k. For first order reaction this slope will be 1 as shown. 

The equation may be rearranged as
log (a – x) =
Thus, a plot of log(a – x) vs. t will be straight line with slope equal to and intercept equal to log a, if the reaction is of first order.
2. Method of integration (Hit and trial method)
The most simple method is the one in which the quantities a, x and t are determined and substituted in the kinetic equations of various orders. The equation which gives the most constant value for the specific rate constant (k) for a series of time intervals is the one corresponding to the order of reaction. If all the reactants are at the same molar concentrations, the kinetic equations are:
k = 2.303/t log_{10}a/((ax) ); for first order reactions.
k = 1/t [1/((ax))1/a]; for second order reactions.
k = 1/t [1/(ax)^{2} 1/a^{2} ]; for third order reactions.
Answer: In Chemical reactions, it is a wellknown fact that raising the temperature increases the reaction rate. An equation that represents the dependence of the rate constant k of a reaction on the absolute temperature T is well known as Arrhenius Equation.
k = A * exp (–Ea/RT)In its original form the preexponential factor A and the activation energy Ea are considered to be temperatureindependent.
Where
k = rate constant, Ea = activation energy, R = 8.314 [ J • mol 1 • K 1 ]
T = absolute temperature in degrees Kelvin, A = preexponential or frequency factor
Note* [A = p • Z, where Z is the collision rate and p is a steric factor. (Z turns out to be only weakly dependant on temperature.)]
Answer: Suppose A is concentration of reactant.
Rate => ( d[A]/dt ) = k[A]n where [A] is in mol / lit and t is in sec
(mol/lit) / sec = k (mol/lit)n
Units of k = mol1n litn1 sec1
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