Take the series

{2, 4, 8, 16, 32} with six terms.

It's formula is

**a _{n} = 2 (2)^{n – 1} = (2)^{n}**

The other is the approach for infinite geometric series..

{2, 1, 0.5, 0.25, 0.125, 0.0625, . . .} .

It's formula is

**a _{n} = 2(1/2)^{n – 1} = (1/2) ^{n - 2}**

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