In elastic collision both momentum and kinetic energy conserves.
Two bodies A and B of masses m1 and m2 are moving with velocity u1 and u2 along the same line. The collision in elastic. After the collision their velocities are v1 and v2.
As linear momentum of the two bodies will conserve
m1u1 + m2u2 = m1v1 + m2v2 ... (i)
For elastic collision, coefficient of restitution, e, is 1. Thus velocity of approach is equal to velocity of separation.
u1 – u2 = v2 – v1 ... (ii)
Solving the two equation we get
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