Diborane the simplest hydride of boron reacts with alkyne to form trialkenylborane. Diborane splits into two BH3 units and the addition of BH3 takes place following Markownikoff’s rule. The addition continues as long as hydrogen is attached to boron atom.
2R – C º CH + B2H6 ® 2R –CH = CH – BH2
R – C º CH + R – CH = CH – BH2 ® (R – CH = CH)2BH
R – C = CH + (R – CH = CH)2BH ® (R – CH=CH)3B
Trialkenylborane on hydrolysis gives alkene.
assignmenthelp.net provides best Online assignment Help service in Alkanes for all standards. Our Tutor provide their high quality and optimized Tutorial help to fulfill all kind of need of Students.
To Schedule a Addition of Boron Hydrides tutoring session
To submit Addition of Boron Hydrides assignment click here.